//题目：输入一行字符，分别统计出其中英文字母、空格、数字和其它字符的个数。
//1.程序分析：利用while语句,条件为输入的字符不为'\n'.
//
//2.程序源代码：
#include "stdio.h"
int main() {
	char c;
	int letters = 0, space = 0, digit = 0, others = 0;
	printf("please input some characters\n");
	while ((c = getchar()) != '\n') {
		if ((c >= 'a' && c <= 'z') || (c >= 'A' && c <= 'Z'))
			letters++;
		else if (c == ' ')
			space++;
		else if (c >= '0' && c <= '9')
			digit++;
		else
			others++;
	}
	printf("all in all:char=%d space=%d digit=%d others=%d\n", letters, space,
			digit, others);
}
